Question

A charge of `15 C` passes through a circuit every `12 s`. If the circuit can generate `6 W` of power, what is the circuit's resistance?

Answer 1

I found: `3.84Omega`

Explanation:

The current will be:
`I=q/t=15/12=1.25A`

The power is:

`P=VI=I^2R` (using Ohm's Law `V=RI`)

so:

`R=P/I^2=6/(1.25)^2=3.84Omega`