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Question #f4b39

1 Answer

May 5, 2016

#|z|=sqrt29#

Explanation:

#"let be ; z=u+v"#

#z=(-5+10)i+(1+1)j#

#z=5i+2j#

#|z|=sqrt(5^2+2^2)#

#|z|=sqrt(25+4)#

#|z|=sqrt29#

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