How many grams of #KCl# are needed to make 500 mL of 2.45 M #KCl#?

Question

66993 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-06T15:52:02

#91.4# grams

#C = (mol)/(volume)#

#2.45M = (mol)/(0.5L)#

#2.45 M * 0.5 L = mol#

#mol = 1.225#

Convert no. of moles to grams using the atomic mass of K + Cl

#1.225 mol * ((39.1 + 35.5)g)/(mol)#

#1.225cancel(mol) * (74.6g)/cancel(mol)#

#=1.225*74.6g#

#= 91.4g#