Question

A charge of `1 C` is at `(-7, 1 )` and a charge of `-3 C` is at `(3, -3)`. If both coordinates are in meters, what is the force between the charges?

Answer 1

`F=-2.3*10^8 N`

Explanation:

`F=k*(q_1*q_2)/r^2`

`r^2=AB^2=116`

`q_1=1C`

`q_2=-3C`

`k=9*10^9`

`F=9*10^9*(1*(-3)*)/116`

`F=-(27*10^9)/116`

`F=-0.23*10^9`

`F=-2.3*10^8 N`