Question

What is the temperature of 350 mL of gas at .85 atm if it has a volume of 920 mL at STP?

Answer 1

`88.3K`

Explanation:

Use the equation:

`(P_1 * V_1)/(T_1) = (P_2*V_2)/T_2`

Where `P_1` is the pressure at STP, `T_1` is the temperature at STP and `V_1` is `0.92L`.

Substitute all the values in.

`[(1 atm)(0.92L)]/(273K) = [(0.85atm)(0.35L)]/T_2`

`(T_2)(0.92L)= (273K)(0.85atm)(0.35L)`

`(T_2)(0.92L)= 81.22`

`(T_2) = 88.3K`