How many moles of CaCl_2 are in 250 mL of a 3.0 M of CaCl_2 solution?

1 Answer
May 7, 2016

0.75mol

Explanation:

C = (n\ mol)/V, where C is concentration, n is number of moles and V is volume in liters.

In this problem, C = 3.0 M and V = 0.25L

Substitute this into the equation.

3.0M = (n\ mol)/(0.25L)

3.0 ((mol)/cancel(L)) * 0.25cancel(L) = 0.75\ mol