A charge of #-2 C# is at #(4, -5)# and a charge of #1 C# is at #(-3 , 4 ) #. If both coordinates are in meters, what is the force between the charges?

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Answer 1 · 2016-05-07T07:12:33

Force #F=138,307,692.3" "#Newtons

The formula for Coulomb's Law

#F=k_e abs(q_1*q_2)/r^2" "#where #k_e=8.99 x 10^9" "##N*m^2*C^(-2)#

#F=k_e abs(q_1*q_2)/r^2" "#

#F=(8.99 x 10^9)*abs((-2)(1))/(sqrt((4--3)^2+(-5-4)^2))^2 #

#F=((8.99 x 10^9)*2)/(sqrt((7)^2+(-9)^2))^2 #

#F=((8.99 x 10^9)*2)/(sqrt((49+81))^2 #

#F=((8.99 x 10^9)*2)/130#

Force #F=138,307,692.3" "#Newtons

God bless......I hope the explanation is useful.