How do you use the rational root theorem to find the roots of #2x^3 + 7x^2 - 77x - 40#?
1 Answer
Explanation:
By the rational root theorem, any rational zeros of this polynomial must be expressible in the form
That means that the only possible rational zeros are:
#+-1/2# ,#+-1# ,#+-2# ,#+-5/2# ,#+-4# ,#+-5# ,#+-8# ,#+-10# ,#+-20# ,#+-40#
This is rather a lot of possibilities to try, but trying each in turn we soon find:
#f(-1/2) = -1/4+7/4+77/2-40 = (-1+7+154-160)/4 = 0#
So
#2x^3+7x^2-77x-40 = (2x+1)(x^2+3x-40)#
To factor the remaining quadaratic find a pair of factors of
Hence:
#x^2+3x-40 = (x+8)(x-5)#
So the other two zeros are