How do you solve the following linear system: # x+y=-6 , 6x-y=5 #?

1 Answer
Gió
May 8, 2016

I found:
#x=-1/7#
#y=-41/7#

Explanation:

I would isolate #x# from the first equation:
#x=-y-6#
and substitute for #x# into the second:
#6(-y-6)-y=5#
solve for #y#:
#-6y-36-y=5#
#-7y=41#
so that #y=-41/7#
using this back into the first equation:
#x=41/7-6#
#x=(41-42)/6=-1/7#

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