Question

How do you write `5^-3 = 1/125` in log form?

Answer 1

`log 10^(5^(-3))=ln e^(5^(-3))=log_b b^(5^(-3))`

Explanation:

Use `log_b b^n=n log_b b=n(1)=n`

Here, `n=5^(-3)` and b is at your choice...