Question

A crane lifts a 487 kg beam vertically at a constant velocity. If the crane does 5.20 x 10^4 of work on the beam find the vertical distance that it lifted the beam?

I understand the equation that needs to be used to solve the problem. What don't I understand is how does the coefficient of gravity(g) which is 9.8m/s plays a role in this question. Can someone kindly explain this part for me?

Answer 1

Vertical distance `d=10.9" "`meters

Explanation:

The only force involve in the crane is the weight `F` of the beam

The force of the weight
`F=mg`

`F=487" "` `kg*(-9.8" "m/sec^2")`

`F=-4772.6" "`Newtons (negative because weight is downward direction)

Force of the crane is equal to weight directed upward (positive)`=+4772.6" "`Newtons

The work `W=F*d" "`where `d=`distance

`d=W/F=(5.2 x 10^4)/4772.6`

`d=10.89552864" "`meters

God bless....I hope the explanation is useful.