Question

How do you find the limit of `(ln x)^2 / x` as x approaches infinity?

Answer 1

I would say that tends to zero.

Explanation:

As `x->oo` you get `oo/oo`...
We can try using de l'Hospital Rule and derive numerator and denominator to get:
`(2(ln(x))1/x)/1=2ln(x)/(x)`
again:
`2(1/x)/1=2/x`
That as `x->oo` tends to `2/oo=0`.