How do you simplify 7^ (log _(7)9 - log_(7)8)?

1 Answer
May 10, 2016

9/8

Explanation:

Say that this equation equals x, so

7^(log_7 9-log_7 8)=x

Now take the log_7 of both sides to get rid of the powers,

log_7 9-log_7 8=log_7 x.

We know that loga-logb=log(a/b), so

log_7 (9/8)=log_7 x

Raise both sides by the base of 7 to remove logarithms, and find the answer

9/8=x