Question

A charge of `54 C` passes through a circuit every `6 s`. If the circuit can generate `63 W` of power, what is the circuit's resistance?

Answer 1

I found `0.66Omega`

Explanation:

You know that current `I` is:
`I=q/t=54/6=9A`
We can now use the fact that power is:
`P=VI=I^2R`
Rearranging:
`R=P/I^2=63/9^2=0.66Omega`