Question

How many moles of solute are present in 1.25 L of a 0.75 M `NaNO_3` solution?

Answer 1

Approx. 1 mole of sodium nitrate.

Explanation:

`"Concentration " =" Amount of substance"/"Volume of solution"`

Thus `"Amount of substance"="Volume"xx"Concentration"`

`=` `1.25*Lxx0.75*mol*L^-1=??*mol`