A projectile is shot at an angle of $\frac{π}{6}$ $pi/6$ and a velocity of $4 \frac{m}{s}$ $4 m/s$ . How far away will the projectile land?

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Answer 1 · 2016-05-12T12:55:49

$x_{m} = 1.41 m$ $x_m=1.41" m"$

$x_{m} = \frac{v_{i}^{2} \cdot sin 2 α}{g}$ $x_m=(v_i^2*sin 2 alpha)/g$

$x_{m} = \frac{4^{2} \cdot sin (2 \cdot \frac{π}{6})}{9.81}$ $x_m=(4^2*sin (2*pi/6))/(9.81)$

$x_{m} = 16 \cdot \frac{sin (\frac{π}{3})}{9.81}$ $x_m=16*sin(pi/3)/(9.81)$

$x_{m} = \frac{16 \cdot 0.866}{9.81}$ $x_m=(16*0.866)/(9.81)$

$x_{m} = 1.41 m$ $x_m=1.41" m"$

A projectile is shot at an angle of pi/6 π6pi/6 and a velocity of 4 m/s4ms 4 m/s. How far away will the projectile land?