Question

How do you solve `ln 4 + 2 ln x = 0`?

Answer 1

I found `x=1/2`

Explanation:

We can first operate on the `2` of the second `ln` to write:
`ln(4)+ln(x)^2=0`
we now use the property of the sum to write:
`ln(4x^2)=0`
we use the definition of log to write:
`4x^2=e^0`
`4x^2=1`
`x^2=1/4`
`x=+-sqrt(1/4)=+-1/2`
where we use only the positive one.