If a projectile is shot at a velocity of #18 m/s# and an angle of #pi/3#, how far will the projectile travel before landing?

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Answer 1 · 2016-05-14T14:03:55

Horizontal distance #x=28.63186029" "#meters

Let #t# be the time required for the projectile to reach the maximum height.

Let #2t# be the time required for the projectile to travel from initial position to the final position at landing.

#t=(-v_0 *sin theta)/g#

#t=(-18 *sin 60^@)/(-9.8)#

#t=(45sqrt3)/49=1.590658905" "#sec

For horizontal distance #x#

#x=v_0*cos theta*2t#

#x=18*cos 60^@*2(1.590658905)#

#x=28.63186029" "#meters

God bless....I hope the explanation is useful.