Question

225 grams of `NH_4NO_3` in 2.5 liters of water has what concentration?

Answer 1

`"Concentration"="Moles of solute"/"Volume of solution"`

Explanation:

Following the above definition, and assuming (reasonably) that the volume does not markedly change upon dissolution of the solute:

`"Concentration"` `=` `(225*cancelg)/(80.04*cancelg*mol^-1)xx1/(2.5*L)` `~=` `1.1*mol*L^-1`.