Question

How many moles of `NaOH` are in 10.0 mL of a 3.00 M solution?

Answer 1

`Molarity=n/V`

`n=M*V`

`n=3.00M*10.0*10^-3L`

n=0.03 mole

Explanation:

here in the formula n=# of moles of solute
and V=liter volume of solution