This problem can be solved in 2 ways:
Method 1:
We have #0.2" bushel" = 1 doz = 2 kg#
#=> 0.2" bushel" = 2 kg#
#=> 1" bushel" = 2/0.2 kg=(2color(red)(0))/(0cancel(.)2) kg=20/2kg#
#=> 1" bushel" = 10 kg#
#=> 0.5" bushel" = 10xx0.5 kg#
#=> 0.5" bushel" = 5 kg#
Method 2:
- First, we find the number of apples in #0.5# bushel.
We have,
#0.20" bushel" = 1 " doz apples" = 12 " apples"#
#=>1" bushel"= 12/0.20#
We need to get a #1# or a multiple of #10# in the denominator.
We know that #0.20 xx 5 = 1#
Multiply the numberator and denominator by 5.
Then, #(12xx5)/(0.20xx5)= 60/1#
#=>1" bushel"= 60 " apples"#
#=>0.5" bushel"= 60xx0.5=30 #
Therefore, #color(red)(0.5 " bushel" = 30" apples"#
- Next we calculate the mass of these apples:
Mass of #12 " apples" = 2 kg#
Mass of #1 " apples" = 2/12 kg#
Mass of #30 " apples" = (2xx30)/12 kg#
#= (2xxcancel30^color(red)(10))/cancel12^color(red)(4) kg#
#= (2xxcancel10^color(red)(5))/cancel4^color(red)(2) kg#
#= (cancel2xx5)/cancel2 kg#
Mass of #30 " apples" = 5 kg#
