What is the molarity of a solution containing 12.0 g of #NaOH# in 250.0 mL of solution?

1 Answer
anor277
May 18, 2016

#"Molarity "="Moles of solute"/"Volume of solution"# #=# #(12.0*g)/(40.00*g*mol^-1)xx(1)/(250.0xx10^-3*L)# #=# #??mol*L^-1#

Explanation:

#"Moles of sodium hydroxide"# #=# #(12.0*g)/(40.00*g*mol^-1)#.

#"Volume of solution"# #=# #250.0xx10^-3*L#

We assume (reasonably) that the sodium hydroxide dissolves in the given volume without affecting the volume.

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