Question

What is the standard form of `y= (-x+3/2x^2)(x-6)`?

Answer 1

`y=3/2x^3-10x^2+6x`

Explanation:

Polynomials in standard form is arranged in such a way that the highest degree term is written first and the next degree lower is written next, and so forth and so on. In other words, the terms of the polynomial must be arranged from highest degree to the lowest.

So for the given problem

`y=(-x+3/2x^2)(x-6)`

expand by multiplication

`y=-x^2+3/2x^3+6x-9x^2`

simplify

`y=3/2x^3-10x^2+6x`

God bless...I hope the explanation is useful.