Question

A projectile is shot at an angle of `pi/4` and a velocity of `16 m/s`. How far away will the projectile land?

Answer 1

`128/5`

Explanation:

This answer is based on if `g=10`
The vertical(`ver`) and horizontal(`hrz`) velocity(`V`) are both `16*sqrt(2)/2=8sqrt2`
Next we calculate the time(`T`) it takes to go up and down
We can use how long it take till the vertical speed equals `0` to get the time, `T=(verV)/g=8sqrt2/10=8sqrt2/5`
Now we can calculate the distance `D=hrzV*T=8sqrt2*8sqrt2/5=128/5`