A projectile is shot at an angle of $\frac{π}{4}$ $pi/4$ and a velocity of $16 \frac{m}{s}$ $16 m/s$ . How far away will the projectile land?

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A projectile is shot at an angle of $\frac{π}{4}$ $pi/4$ and a velocity of $16 \frac{m}{s}$ $16 m/s$ . How far away will the projectile land?

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Answer 1 · 2016-05-19T02:24:21

$\frac{128}{5}$ $128/5$

Explanation:

This answer is based on if $g = 10$ $g=10$
The vertical( $v e r$ $ver$ ) and horizontal( $h r z$ $hrz$ ) velocity( $V$ $V$ ) are both $16 \cdot \frac{\sqrt{2}}{2} = 8 \sqrt{2}$ $16*sqrt(2)/2=8sqrt2$
Next we calculate the time( $T$ $T$ ) it takes to go up and down
We can use how long it take till the vertical speed equals $0$ $0$ to get the time, $T = \frac{v e r V}{g} = 8 \frac{\sqrt{2}}{10} = 8 \frac{\sqrt{2}}{5}$ $T=(verV)/g=8sqrt2/10=8sqrt2/5$
Now we can calculate the distance $D = h r z V \cdot T = 8 \sqrt{2} \cdot 8 \frac{\sqrt{2}}{5} = \frac{128}{5}$ $D=hrzV*T=8sqrt2*8sqrt2/5=128/5$

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A projectile is shot at an angle of $\frac{π}{4}$ $pi/4$ and a velocity of $16 \frac{m}{s}$ $16 m/s$ . How far away will the projectile land?

1 Answer

Explanation:

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A projectile is shot at an angle of $\frac{π}{4}$ $pi/4$ and a velocity of $16 \frac{m}{s}$ $16 m/s$ . How far away will the projectile land?