Question

What is the energy of a photon that emits a light of frequency `6.42 * 10^14` `Hz`?

Answer 1

We use the Planck relation, `E=hnu`, where `h` `=` `"Planck's constant"` `=` `6.626070040(81)xx10^(−34)J*s`

Explanation:

Thus `E` `=` `6.626070040(81)xx10^(−34)J*sxx6.42xx10^14*s^-1` `~=` `10^(-20) J`.