What is the energy of a photon that emits a light of frequency $6.42 \cdot 10^{14}$ $6.42 * 10^14$ $H z$ $Hz$ ?

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What is the energy of a photon that emits a light of frequency $6.42 \cdot 10^{14}$ $6.42 * 10^14$ $H z$ $Hz$ ?

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Answer 1 · 2016-05-21T14:21:43

We use the Planck relation, $E = h ν$ $E=hnu$ , where $h$ $h$ $=$ $=$ $Planck's constant$ $"Planck's constant"$ $=$ $=$ $6.626070040 (81) \times 10^{- 34} J \cdot s$ $6.626070040(81)xx10^(−34)J*s$

Explanation:

Thus $E$ $E$ $=$ $=$ $6.626070040 (81) \times 10^{- 34} J \cdot s \times 6.42 \times 10^{14} \cdot s^{- 1}$ $6.626070040(81)xx10^(−34)J*sxx6.42xx10^14*s^-1$ $≅$ $~=$ $10^{- 20} J$ $10^(-20) J$ .

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What is the energy of a photon that emits a light of frequency $6.42 \cdot 10^{14}$ $6.42 * 10^14$ $H z$ $Hz$ ?

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What is the energy of a photon that emits a light of frequency $6.42 \cdot 10^{14}$ $6.42 * 10^14$ $H z$ $Hz$ ?