How do you solve #-w^2-3w-7 = -2w^2 + 3#?

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Answer 1 · 2016-05-21T20:51:09

#w=5#

#w=-2#

#-w^2-3w-7=-2w^2+3#

Rearrange the equation and combine like terms:

#w^2-3w-10=0#

Factorise the equation:

#(w-5)(w+2)=0#

Now you can solve for #w#:

#w=5# or #w=-2#