How do solve the following linear system?: $4x+2y=6 , 3x + y = -20$ ?

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Answer 1 · 2016-05-22T15:23:54

The solution for the system of equations is:

$color(green)(x = -23$

$color(green)(y =49$

$4x + color(blue)(2y) = 6$ ..............equation $(1)$
$3x + y =- 20$ , multiplying by $2$

$6x + color(blue)( 2y) =- 40$ ......equation $(2)$

Solving by elimination:

Subtracting equation $2$ from equation $1$ :

$4x + cancelcolor(blue)(2y) = 6$

$-6x - cancelcolor(blue)( 2y) =40$

$-2x = 46$

$x = 46 /(-2)$

$color(green)(x = -23$

Finding $y$ from equation $2:$
$3x + y =- 20$

$y =- 20 - 3x$

$y =- 20 - 3 xx (-23)$

$y =- 20 + 69$

$color(green)(y =49$

How do solve the following linear system?: 4x+2y=6 , 3x + y = -20 4x+2y=6 , 3x + y = -20 ?