Question

How do you write the standard from of the equation of the circle given center is (-2,5) and whose diameter is 12?

Answer 1

`(x+2)^2+(y-5)^2=36`

Explanation:

The standard form of the equation of a circle is.

`color(red)(|bar(ul(color(white)(a/a)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(a/a)|)))`
where (a ,b) is the centre and r, the radius.

Here the centre = (-2 ,5) and radius = 6

`rArr" equation is " (x+2)^2+(y-5)^2=36`