How do you find the center-radius form of the equation of the circle given Center (0,-2), radius 6?

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Answer 1 · 2016-05-23T23:01:45

#(x-0)^2+(y-(-2))^2=6^2#

The center-radius form of the equation of a circle is:

#(x-h)^2+(y-k)^2 = r^2#

where #(h, k)# is the center and #r# the radius.

So in our example, we can write:

#(x-0)^2+(y-(-2))^2=6^2#

If we are slightly less fussy about the form, this simplifies to:

#x^2+(y+2)^2 = 36#