Question

How do you solve `secx-sqrt2 = 0` algebraically for all values of `x` in `0°<=x<360°`?

Answer 1

`pi/4, (7pi)/4`

Explanation:

`sec x = 1/(cos x) = sqrt2`
`cos x = 1/sqrt2 = sqrt2/2` --> `x = +- pi/4`
Co-terminal arc to `-pi/4` --> arc `(7pi)/4`
Answers for `(0, 2pi)`
`pi/4 and (7pi)/4`