Question

How do you simplify `(3x)/(6x^2) times (2y-6)/(y-3)`?

Answer 1

It is

`(3x)/(6x^2) times (2y-6)/(y-3)=(3x)/(2x*3x) times ((2*(y-3))/(y-3))= (cancel(3x))/(2x*cancel(3x)) times ((2*cancel(y-3))/cancel(y-3))= 1/(2x) times 2=1/(cancel2*x)*cancel2=1/x`