How do you graph #y = log _4 (x) - 3#?

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Answer 1 · 2016-05-27T09:57:03

The graph of y vs log x on a semi-log graph paper will be a straight line with slope #1/log 4#. with y-interceot = #-3#.

Use log_4 x= log x/log 4.

Here, #y = log_4 x-3=log x/log 4-3#.

y is a linear function of X = log x..

If X-graduation is in the logarithmic scale

( 1 for log 10, 2 for log 100, ..., n for #log 10^n#),

the graph paper is semi-logarithmic.

On this graph paper, the graph for the given equation will be a

straight line, with #1/log 4 = 1.661#, nearly, with y-intercept #= -3#.