How do you write $8.2 times 10^-4$ in standard notation?

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Answer 1 · 2016-05-28T21:05:46

It is 0.00082.

The $10^-4$ tells you that you have to write 4 zeros including the first one before the dot. So the number is
$8.2\times10^{-4}=0.00082$

Answer 2 · 2016-05-28T21:15:11

Emphasising the point made in the other solution

$8.2xx10^(-4)=0.00082$

Given: $8.2xx10^(-4)$

This is the same as

$8.2/(10xx10xx10xx10)$

$=0.82/(10xx10xx10)$

$=0.082/(10xx10)$

$=0.0082/(10)$

$=0.00082$

How do you write 8.2 times 10^-48.2 times 10^-4 in standard notation?