What is the molarity of .50 g of #Na# dissolved in a 1.5 L solution?

1 Answer
anor277
May 29, 2016

In aqueous solution, approx. #0.015*mol*L^-1# with respect to sodium ion.

Explanation:

#Na+H_2O rarr NaOH(aq) + 1/2H_2(g)uarr#

#"Moles of sodium metal"# #=# #(0.50*g)/(22.99*g*mol^-1)#

#"Concentration"# #=# #"Amount in moles"/"Volume of solution (L)"#

#=# #(0.50*g)/(22.99*g*mol^-1)xx1/(1.5*L)#

#=# #??mol*L^-1#.

Under standard conditions (#"298K, 1 atm"#), what volume of gas will be evolved?

Note that I could have dissolved the sodium in mercury metal; in fact this is often done in synthetic laboratories. Now that would be quite a heavy solution.

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