How many moles of solute are contained in 200 milliliters of a 1 M solution?

1 Answer
May 29, 2016

Such a volume contains 0.200 mol of solute.

Explanation:

"Concentration" = "Moles of solute"/"Volume of solution".

Typically, we perform the calculation: C=n/V, where n is the amount of solute in moles, V the volume of the solution in "litres", and C, the concentration in mol*L^-1.

Given C=n/V, then n = CxxV.

Here, n = 200xx10^-3*Lxx1*mol*L^-1 = 0.200*mol. This calculation is consistent dimensionally, as when L cancel, we get an answer in mol.