Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you know if the series #((-1)^n)*sqrt(n)/(ln(n))# converges or diverges for (n=2, ∞) ?

1 Answer

May 30, 2016

The series is divergent

Explanation:

#sqrt k > log(k)# for #k = 2,3,4,...#

Related questions

What is the Direct Comparison Test for Convergence of an Infinite Series?
How do you use the direct comparison test for infinite series?
How do you use the direct comparison test for improper integrals?
How do you use the direct Comparison test on the infinite series #sum_(n=1)^oo5/(2n^2+4n+3)# ?
How do you use the direct Comparison test on the infinite series #sum_(n=1)^ooln(n)/n# ?
How do you use the direct Comparison test on the infinite series #sum_(n=2)^oon^3/(n^4-1)# ?
How do you use the direct Comparison test on the infinite series #sum_(n=1)^oo9^n/(3+10^n)# ?
How do you use the direct Comparison test on the infinite series #sum_(n=1)^oo(1+sin(n))/(5^n)# ?
How do you use the direct Comparison test on the infinite series #sum_(n=1)^ooarctan(n)/(n^1.2)# ?
How do you use basic comparison test to determine whether the given series converges or diverges...

See all questions in Direct Comparison Test for Convergence of an Infinite Series

Impact of this question

6594 views around the world

You can reuse this answer
Creative Commons License