Question

A gas at 52°C occupies 6.8 L at a pressure of 1.5 atm. What will the pressure be at -43°C if the volume is reduced to 2.2 L?

Answer 1

The combined gas law holds that `(P_1V_1)/T_1` `=` `(P_2V_2)/T_2`. Thus `P_2~=3*atm`.

Explanation:

`P_2=(P_1V_1T_2)/(T_1V_2)` `=` `(1.5*atmxx6.8*Lxx230*K)/(325*Kxx2.2*L)` `=` `??*atm`

Note that we had to convert all temperature readings to the absolute scale, as we typically do for gas problems.