Can you prove #costheta = sectheta-sinthetatantheta#?

1 Answer
Jun 1, 2016

Yes, I can.

Explanation:

We ahve #sec(theta)=1/cos(theta)# and #tan(theta)=sin(theta)/cos(theta)#.
I substitute:

#cos(theta)=1/cos(theta)-sin(theta)sin(theta)/cos(theta)#

#cos(theta)=(1-sin(theta)^2)/cos(theta)#

#cos(theta)^2=1-sin(theta)^2#

#cos(theta)^2+sin(theta)^2=1#

That is the fundamental identity of trigonometry.