Question

How do you convert 45°C to Fahrenheit?

Answer 1

Recall the formula to convert this.

`\mathbf(T_C = 5/9(T_F - 32))`

Of course, `T_C` is the temperature in `""^@ "C"`, and `T_F` is the temperature in `""^@ "F"`.

Let's test this to make sure. I know that `100^@ "C" = 212^@ "F"` is the boiling point of water, so let's see if that works.

`color(green)(T_C) = 5/9(212 - 32)`

`= 5/9(180)`

`= 5*20 = color(green)(100^@ "C")`

Yep. Now use it on `45^@ "C"`.

`45 = 5/9(T_F - 32)`

`405/5 = T_F - 32`

`81 + 32 = color(blue)(113^@ "F" = T_F)`