Question

How do you condense `1/2[log_4(x+1)+2log_4(x-1)] + 6log_4x`?

Answer 1

It is

#1/2[log_4(x+1)+2log_4(x-1)] + 6log_4x => 1/2[log_4(x+1)+log_4(x-1)^2]+log_4x^6=> log_4[sqrt((abs(x+1))*(x-1)^2)*x^6]#