Question

How do you graph and solve `7|x+2| +5>4`?

Answer 1

verified `AA x in RR`

Explanation:

let `f(x)=|x+2|`

graph{y=|x+2| [-10, 10, -5, 5]}

We see that `f(x)>=0 AA x in RR`

so `f(x)>(4-5)/7`
then
`|x+2|> -1/7 AA x in RR`