How do you find abs(-5i)?

1 Answer
Jun 6, 2016

Apply the definition |a+bi| = sqrt(a^2+b^2) to find that

|-5i| = 5

Explanation:

The modulus of a complex number a+bi, denoted |a+bi|, is given by

|a+bi| = sqrt(a^2+b^2).

and is an extension of the absolute value function, which applies to reals. The latter represents the distance from the real number to 0 on the number line, and the former represents the distance of the complex number to the origin on the complex plane.

Applying this definition to our given complex number, we have:

|-5i| = |0+(-5)i|

=sqrt(0^2+(-5)^2)

=sqrt(0+25)

=sqrt(25)

=5