Question

How do you convert 27.6 g `Ar` to atoms?

Answer 1

Well, I know there are `"Avogadro's number"` of `"Ar"` atoms in a mass of `39.95*g`.

Explanation:

Thus `"Argon atoms"` `=` `(27.6*g)/(39.95*g*mol^-1)xx6.022xx10^23" argon atoms "mol^-1` `=` `??" argon atoms"`

Answer 2

`4.15x10^23` atoms of Argon

Explanation:

To change 27.6 g of Argon to atoms we begin by converting the grams of Argon to moles using a conversion factor of 1 mole equal to the mass of Argon from the periodic table.

`27.6 cancel(g) ((1mol)/(39.95cancelg))=0.69 mol`

Now convert moles to atoms using Avogadro's number of `6.02x10^23`

`0.69cancel(mol)((6.02x10^23atms)/(1cancel(mol)))=`

`4.15x10^23` atoms of Argon