If $f (x) = x^{2} - x$ $f(x)=x^2-x$ , how do you find $3 f (x)$ $3f(x)$ ?

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Answer 1 · 2016-06-06T08:55:56

$3 x^{2} - 3 x$ $3x^2-3x$

This just means multiply f(x) by 3.

$\Rightarrow 3 \times f (x) = 3 (x^{2} - x) = 3 x^{2} - 3 x$ $rArr3xxf(x)=3(x^2-x)=3x^2-3x$

If f(x)=x2−xf(x)=x^2-x, how do you find 3f(x)3f(x)?