Question

Given `((x + 3)(x - 4)) / ((x + 3)(x + 1)`# how do you find the limit as x approaches -3?

Answer 1

`7/2`

Explanation:

as `xto-3` , the factor (x+3) on the numerator and denominator will be zero and we will obtain.

`0/0" which is undefined."`

By cancelling we can eliminate this situation.

`((cancel(x+3))(x-4))/(cancel((x+3))(x+1))=(x-4)/(x+1)`

and now we have a simplified function.

`rArrlim_(xto-3) (x-4)/(x+1)=(-3-4)/(-3+1)=7/2`