Question

How do you find equation of line through point (5, -2) parallel to line 3y+7=-8?

Answer 1

`y=-2`

Explanation:

Subtract `color(blue)(7)` from both sides

`color(brown)(3y+7=-8" "->" "3y+7color(blue)(-7)=-8color(blue)(-7))`

`3y=-15`

Divide both sides by 3

`3/3 y=-15/3`

`1xxy=-5`

`y=-5" "larr" Parallel to the x-axis"`

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`y=-2` is parallel to the other equation and passes through the point (5,-2).