Question

How do you solve `log_9x = 1.5`?

Answer 1

I found `x=27`

Explanation:

We can write it trying to manipualte `1.5` into `3/2`:
`log_9(x)=3/2`
we use the definition of log:
`x=9^(3/2)`
and the property of exponents:
`x=sqrt(9^3)`
`x=27`