Question

For what values of x, if any, does `f(x) = 1/((x+12)(x-1))` have vertical asymptotes?

Answer 1

vertical asymptotes x = -12 , x = 1

Explanation:

Vertical asymptotes occur as the denominator of a rational function tends to zero. To find the equation/s set the denominator equal to zero.

solve: (x+12)(x-1) = 0 → x = -12 , x = 1 are the asymptotes.
graph{1/((x+12)(x-1) [-20, 20, -10, 10]}