Question

What is the molarity of an `H_2SO_4` solution if 0.25 liter of the solution contains 0.75 mole of `H_2SO_4`?

Answer 1

The solution will have a concentration of `"3 M"` sulfuric acid.

Explanation:

The molarity, M, of a solution is determined by dividing the number of moles by the volume in liters.

`M=n/V`, where `"M"` is the molarity, `n` is the moles of solute, and `V` is the volume of the solution in liters.

Substitute the given values into the molarity equation and solve.

`M=(0.75"mol")/(0.25"L")="3.0 M H"_2"SO"_4`, pronounced three molar sulfuric acid.