If $f (x) = x^{2} - x$ $f(x)=x^2-x$ , how do you find $f (2 x)$ $f(2x)$ ?

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If $f (x) = x^{2} - x$ $f(x)=x^2-x$ , how do you find $f (2 x)$ $f(2x)$ ?

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Answer 1 · 2016-06-13T18:45:21

$4 x^{2} - 2 x$ $4x^2-2x$

Explanation:

All that is required here is to substitute x = 2x into the right side in the same way that is done for a numeric value.

$f (x) = x^{2} - x$ $f(x)=x^2-x$

f(2) means substitute x = 2

$\Rightarrow f (2) = 2^{2} - 2 = 4 - 2 = 2$ $rArrf(2)=2^2-2=4-2=2$

In the same way:

$f (2 x) = {(2 x)}^{2} - (2 x) = 4 x^{2} - 2 x$ $f(2x)=(2x)^2-(2x)=4x^2-2x$

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If $f (x) = x^{2} - x$ $f(x)=x^2-x$ , how do you find $f (2 x)$ $f(2x)$ ?

1 Answer

Explanation:

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If $f (x) = x^{2} - x$ $f(x)=x^2-x$ , how do you find $f (2 x)$ $f(2x)$ ?